Question

calculate the heat produced in calorie when a current of 0.1A is passed through wire of resistance 41.8 ohms for 10 min
pls help with this​

Answer 1

Answer:

1053.36 cal

Explanation:

We know that,

H= I^2 * R * t

Therefore,

Heat produced (H)= (0.1*0.1) A^2* 41.8 ohm * (10*60 s) J

= 250.8 J

= (250.8 * 4.24) cal

= 1053.36 cal (ans)