Calculate the heat produced in calorie when a current of 0.1A is passed through a wire of resistance 41.8Ω for
5 minutes.
Answers
Answered by
2
Answer:
Answer - 125.4J
Explanation:
Heat produce = (l)^2 × R × time in second
= (0.1)^2 × 41.8 × (5×60)
= 0.01 × 41.8 × 300
= 3 × 41.8
= 125.4 J
Heat = 125.4 J
1J = 4.2 calories
heat = 125.4 /4.2
= 30 calorie
✌️ Hope it's helpful for u ❤️
Similar questions