Question

Calculate the heat produced when 96000 coulombs of charge is transferred in 1hour through a potential difference of 50 volts​

Answer 1

Answer:

Charge (Q) = 96000 C

Time (t) = 1hr = 60 x 60 = 3600 s

Potential difference (V) = 50 V

Let us calculate current (I)

I = Q/t

I = (96000)/(3600)

I = (80/3) A

Let us calculate the quantity of heat generated by using the formula

H = V × I × t

H = 50 × (80/3) × 3600

H = 4.8 × 106 J

Therefore, the heat generated is 4.8 x 106 J.

Answer 2

Answer:

Given parameters

Charge (Q) = 96000 C

Time (t) = 1hr = 60 x 60 = 3600 s

Potential difference (V) = 50 V

Let us calculate current (I)

I = Q/t

I = Q/tI =  (96000)/(3600)

I = Q/tI =  (96000)/(3600)I = (80/3) A

Let us calculate the quantity of heat generated by using the formula

H = V × I × t

H = V × I × tH = 50 × (80/3) × 3600

H = V × I × tH = 50 × (80/3) × 3600H = 4.8 × 106 J

Therefore, the heat generated is 4.8 x 106 J.

Explanation:

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