Question

Calculate the heat produced when 96000 culomb of charge is transffered in 1 hr through potential difference of 50 volt.

Answer 1

Explanation:

Q= 96000 c

v= 50 v

t =1h = 3600sec

H = VIT

I =Q/T= 9600/3600

H = V Q

50 multiply by 96000

=4800000j

Answer 2

Answer:

Given charge Q = 96000 coulomb.

time = 1hr = 60 x 60 = 3600s.

Potential difference {V} = 50v

According to formula: H= VIT -(i)

Also I = Q/T

∴I  = 96000/3600 =80/3= Ampere

putting value of I = 80/3 Ampere in (i)

H=50 X 80/3 X 60 X 60 = 4.8 X 10²×³joule

Heat is generated that is 4.8 X 10²×³ joule