calculate the heat required to melt 5 kg of ice at 0 degree celsius
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One gram of ice required 80 cal of heat to convert to one gram of water at 0 degree
It would take 80*5*1000 =400000 cal to melt ice at 0 degree
It would take 80*5*1000 =400000 cal to melt ice at 0 degree
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Heat required at 0 deg C, to melt ice at the same temperature to become water -- is called the latent heat of fusion. It is equal to 79.8 Cal / gm of ice or 333.55 Joules / gm.
Heat required = 5 * 1000 * 79.8 = 399 kilo Calories
or 5 * 1000 * 333.55 = 1, 667.75 Kilo Joules
= 1.66775 mega Joules.
Heat required = 5 * 1000 * 79.8 = 399 kilo Calories
or 5 * 1000 * 333.55 = 1, 667.75 Kilo Joules
= 1.66775 mega Joules.
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