calculate the heat required to melt a block of ice of mass 20 gram at -20 degree calcies into water at 0 degree calcies.Given specific heat of ice 0.5cal/gram. latent heat of ice 80 cal/gram
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Answer:
140 calorie
Explanation:
(m×L) + (m×c×∆T)
(20×80) +(20×0.5×(-20-0))
160+(-20)
140 cal
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