calculate the heat supplied to raise the temperature of 2 kg of water from 25 degree Celsius to its boiling point .The Cs of water is 4.184 joule per Kelvin gram. How long will a 2 kilowatt heater take to supply this energy?
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Answer:
mass=2kg
∆temp=100-25=75°C
c=4184 J kg^-1 °C^-1
Q=mc∆t
= 2* 75 *4184
=627600J
Power of the heater=2000W =2000 Js^-1
P=Q/t(time)
t=Q/P
=313.80s
=5.23minutes(ans)
Have a nice day!
-srijan
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