Question

calculate the heat transfer from inner layer of the
skin to the outer layer of the skin having the thickness
of 1 cm
and surface of area of 1.5 m² consider
the skin temperature as
34°c and the temperature

of the body under normal conditions
as 37°C​

Answer 1

The rate of heat transfer from the inner layer to the outer layer of the skin will be equal to  0.045k J/sec

Explanation:

Given,

• The outer layer of the skin have a thickness ,l of 1 cm or 0.01m
• The surface area,A is 1.5 square metres.
• The temperature of the the body is 37 degree Celsius and outlet temperature is 34 degrees celsius.
• Hence the difference of temperature,dt is equal to 3 degree Celsius

Let us consider k as the heat constant of the skin.

The rate of transfer of heat =$\frac{kAdt}{l}$

=  K x 1.5 x 3 / 0.01 = 0.045k J/sec