Question

Calculate the heat transfer rate per unit area through a copper plate0.045 m thick whose one face is maintained at 350 o and the other face at 50 o C. Thermal conductivity of Copper is 370 o W/m o C *​

Answer 1

Answer:

2.446 MW/m sq

Explanation:

Answer 2

2.466 x 106  W/ sq. m

Explanation:

Electric Circuit Theory has Ohm’s Law: I = V/R

Fourier’s Equation have Q = dt /(dx/KA)

Thermal  Resistance  (dx/KA) is analogous to electrical resistance R, Q is analogous to electrical current  ‘I’ and Temperature difference ‘dt’ is analogous to electrical voltage difference.

Therefore rules for combining electrical resistances in series and parallel will apply equally to the combination of thermal resistances.

Calculate the rate of heat transfer per unit area through a copper plate 45 mm thick, whose one face at 350°C and the other face at 50°C. Take thermal conductivity of copper as 370 W/m °C.

Q/A  = -K dt/dx =  -370 (50 -350)/0.045 = 2.466 x 106  W/ sq. m