Calculate the height above the Earth’s surface at which the valueof acceleration due to gravity reduces to half its value on theEarth’s surface. Assume the Earth to be a sphere of radius6400 km.
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g' = G M / d²
g = G M / R² , R = 6400 km
g' / g = 2 given
g'/g = R²/d² => d = R √(g/g') = 6400 √2 km
g = G M / R² , R = 6400 km
g' / g = 2 given
g'/g = R²/d² => d = R √(g/g') = 6400 √2 km
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