calculate the height of a water column which will exert on its base the same pressure as the 70cm column of mercury. Density of mercury is 13.6 g/cm^3.
Answers
Answered by
32
We know,
P=density×height of liquid column×g
P(mercury)=13.6×980×70=932960dyne\cm
Now h of wayercolumn with same ptesdure=h
=pressure\density×g
=932960/980
=952cm
P=density×height of liquid column×g
P(mercury)=13.6×980×70=932960dyne\cm
Now h of wayercolumn with same ptesdure=h
=pressure\density×g
=932960/980
=952cm
Answered by
56
Pressure = hdg
P₁ = P₂
h₁d₁g = h₂d₂g
h₂ = h₁d₁ / d₂
= (70 cm × 13.6 g/cm³) / (1 g/cm³)
= 952 cm
= 9.52 m
Height of water column is 9.52 m
P₁ = P₂
h₁d₁g = h₂d₂g
h₂ = h₁d₁ / d₂
= (70 cm × 13.6 g/cm³) / (1 g/cm³)
= 952 cm
= 9.52 m
Height of water column is 9.52 m
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