Question

calculate the height of the trapezium below given that /bc/=10cm /ad/=16cm and it's area is 104 cm square​

Answer 1

$\large\fcolorbox{red}{cyan}{8\:cm}$

Step-by-step explanation:

• Side a = 10 cm

• Side b = 16 cm

• Height (h) = ?

• Area = ?

$= > \boxed { \bf\color{red}{area = \frac{1}{2} \times( a + b )h}} \\ = > \frac{1}{2} \times (10 + 16) \times h = 104 \\ = > \frac{1}{2} \times 26 \times h = 104 \\ = > 13 \times h = 104 \\ = > h = \frac{104}{13} \\ = > \boxed{h = 8 \: cm}$