Question

Calculate the height of water column which exerts the same pressure as 72 cm of Mercury column. Given density of mercury is 13600 kg per metre cube(kg/m3)

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Answer 1

$\sf\large{\underbrace{h{(water)} \implies 9792\:m}}$

$\sf\large{Presure\:will\:remain\:same\:in\:both\:liquids.}$

$\sf\large{\underline{\underline{Hence,}}}$

$\sf\large{ \: \: \: \: \: \: \: \: \: \: Pressure = p × g × h}$

$\sf\large{Where,}$

$\sf\large{p = density\:of\:liquid}$

$\sf\large{ g = acceleration\:due\:to\:gravity}$

$\sf\large{h = height\:of\:the\:column}$

$\sf\large{\underline{\underline{So}}}$

$\sf{\implies P{(mercury)}× g × h{(mercury)} = P{(water)} × g × h{(water)}}$

$\sf{\implies p{(mercury)} × h{(mercury)} = p{(water)} × h{(water)}}$

$\sf\large{\underline{\underline{Given:}}}$

$\sf\large{\implies p{(mercury)} = 13600\:kg\:m^{-3}}$

$\sf\large{\implies h{(mercury)} = 72\:cm = 0.72\:m}$

$\sf\large{\implies p{(water)} = 1\:h{(water)} = ....?}$

$\sf\large{\underline{\underline{Hence:}}}$

$\sf\large{\implies h{(water)} = \dfrac{13600× 0.72}{1}}$

$\sf\large{\implies h{(water)} = 9792.00\:m}$