Question

calculate the height of which water will rise in a capillary tube of diameter 1 × 10^-3 m​

Answer 1

Answer:

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Answer 2

$\bold{Answer\;:-}$

Given :-

• Diameter of the capillary tube = 1 × 10-³ m

Let's assume as you have not mentioned in the question :-

• Surface tension of water = 0.072 N/m

• Angle of contact = 0°

• Density of water = 1 g/cm³ = 1000 kg/m³

To find :-

• The height of which water will rise in a capillary tube = h

By using the formula,

• h = 2Tcosθ / r*ρ*g

[ Refer to the attachment for the calculation! ]

• h = 2.94 cm

$\bold{Hope\;it \; helps\;!}$