Question

Calculate the horizontal reaction at support 0 of 15 kg slender rod which is rotating at
constant angular velocity of 2 rad/s.
10 N-m
2 rad/s
5 m
A) 100 N B) 150 N c) 200 N D) 50 N​

Answer 1

• Consider the given values

• Mass of the slender is=15 kg

• Angular velocity is=2 rad/s

• based on given data draw the diagram

• so we have,

• F=\int\limits^L_0 {pAdt t w^{2} } , 0
• ∫LpAdttw 2
• [F=mrw^{2} ][F=mrw 2 ]

• F=2}w^{2} }{2} ][ 2pAt 2 w 2 ]

• F={2}w^{2} }{2} 2pAL 2 w 2

• m=pAL

• F=w^{2} }{2} 2mLw 2
• F=15*5*4}{2} 215∗5∗4

• F=150N

Hence,

$B) 150 N c$

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Answer 2

✪ Consider the given values

✪Mass of the slender is=15 kg

✪Angular velocity is=2 rad/s

✪based on given data draw the diagram

so we have,

✪F=\int\limits^L_0 {pAdt t w^{2} } , 0

∫LpAdttw 2

[F=mrw^{2} ][F=mrw 2 ]

✪F=2}w^{2} }{2} ][ 2pAt 2 w 2 ]

✪F={2}w^{2} }{2} 2pAL 2 w 2

✪m=pAL

✪F=w^{2} }{2} 2mLw 2

✪F=15*5*4}{2} 215∗5∗4

✪F=150N

Hence,it is proved that B)150N is the correct answer of your given Question

Hope it helps!

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