Question

Calculate the horizontal reaction at support o of 15 kg slender rod which is rotating at constant angular velocity of 2 rad/s

Answer 1

The horizontal reaction at support "O" is 150N

Explanation:

Consider the given values

Mass of the slender is=15 kg

Angular velocity is=2 rad/s

based on given data draw the diagram

so we have

F=$\int\limits^L_0 {pAdt t w^{2} } \,$   $[F=mrw^{2} ]$

F=$[\frac{pAt^{2}w^{2}  }{2} ]$

F=$\frac{pAL^{2}w^{2}  }{2}$

m=pAL

F=$\frac{mLw^{2} }{2}$

F=$\frac{15*5*4}{2}$

F=150N

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