Calculate the hydrolysis constant for nh4cl and the oh- concentration in 0.1 molar nh4cl solution . KB of nh4oh is 1.7 5 X 10^- 5 what is its PH value
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Answer:
Degree of Hydrolysis = 2.39 x 10^-5
pH = 5.13
Explanation:
salt of strong acid and weak base
let x be the degree of hydrolysis
Formula would be;
X = root of (kw / kb × c )
kw = 10^-14
c= 0.2 M
kb = 1.75 × 10^-5
Putting the values,we get
Degree of Hydrolysis = x= 2.39 ×10^-5
For pH;
ph = ½ (phw - logc -phb)
= 1/2(14 –log 0.1 - 4.74)
pH = 5.13
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