Math, asked by gopalkrishnathumar, 4 months ago

Calculate the hydrostatic pressure exerted by water at the bottom of a beaker. Take the depth of water as 45 cm. (g=9.8m/second square)

Answers

Answered by vivekanandrai138
4

Step-by-step explanation:

Gravity = 9.8m/s²

H= 45/100 =0.45m

Density = 1000 pa/m³

dhudrstatic pressure =

h \times d \times g

1000 \times 0.45 \times 9.8 = 4410

answer

Answered by acoldplayluver
1

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