Calculate the Impulse necessary to stop a
travelling at 72 kmph.
2000kg car
Answers
Answer:
Explanation:
Given :
- Initial velocity (u) = 72 km/h
- Final velocity (v) = 0 km/h
- Mass of a car (m) = 2000 kg
To Find :
- Impulse, J.
Formula to be used :
- J = Δp
Here,
- J = impulse
- Δp = Change in momentum
Solution :
★ Converting units,
Initial velocity = 72 km/h
⇒ v = 72 × 5/18
⇒ v = 20 m/s
Final velocity = 0 km/h
⇒ v = 0 × 5/18
⇒ v = 0 m/s
★ Impulse,
J = Δp
.°. J = m(v - u)
⇒ J = 2000(0 - 20)
⇒ J = 2000 × -20
⇒ J = -40000 N-S
Hence, Impulse is -40000 N-S.
✵ This question says that there is a car of mass 2000 kg. It's travelling at speed of 72 km/h. Now it says that we have to calculate the impulse necessary to stop the car.
❈ Mass = 2000 kg
❈ Speed ( Final velocity ) = 0 km/h
❈ Initial velocity = 72 km/h
Note : The final velocity be 0 because there is a brake that time means when an object is on rest the it's velocity be 0 by itself.
❈ Impulse necessary to stop the car.
❈ Impulse necessary to stop the car = - 40000 N-S
❈ Finding impulse formula.
❈ Impulse = ∆p
✵ ∆p means Momentum change.
✵ Impulse also denote as J.
✵ Mass as m
✵ Final velocity as v
✵ Initial velocity as u
❈ To solve this question we have to use the formula to find Impulse. But there is a twist and it's the velocities are in km/h and as we know that we have to convert them in m/s So (conventing them) noe we get these in m/s easily. Now, using formula but we have to put v , u or else in this formula. ( putting the values ) we get our final result very easily! And the final result is 40000N-S.
☃ Convertation of km/h into m/s
~ Final velocity
➝ Final velocity = 72 ×
➝ Final velocity = 4 × 5
➝ Final velocity = 20 m/s
~ Initial velocity
➝ Initial velocity = 0 ×
➝ Initial velocity = 0 m/s
☃ Finding impulse
➝ Impulse = ∆p
➝ Impulse = m(v-u)
➝ Impulse = 2000(0-20)
➝ Impulse = 2000(-20)
➝ Impulse = 2000 × -20
➝ Impulse = -40000 N-S
- Therefore, Impulse = -40000 N-S