calculate the impulse of an average force of 2N acting on a body for a time interval of 10 milliseconds
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Answer:
F=10N =m =20 kg, T =10s
a=m
f =20
t =10
=0.5m/s
=2
v =v+a+=0+0.5×10=5m/s
change in momentum
=m(v-v) =20(5-0)=100kg m /s answer
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