Question

calculate the increase in entropy in the evaporation of one mole of water.latent heat of vaporisation of water is 2.26kj/g​

Answer 1

Answer:

Heat of vapourisation at 100  

0

C=540 Cal/gm

Molar heat of vapourisation =540×18 Cal/gm

ΔS=  

T

q  

rev

​  

 

​  

=  

373

540×18

​  

 

ΔS=26.06 Cal/gm

Explanation:

Answer 2

Answer:

Heat of vapourisation at 100°C=540 Cal/gm

Molar heat of vapourisation =540×18 Cal/gm

ΔS= qrev/t=540×18/373

ΔS=26.06 Cal/gm