Calculate the initial pressure inside a scuba tank before it cooled from 1000 °C to 25.0 °C. The final pressure in the tank is 30.43 atm
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Given:
Initial temperature, T1 = 1000 °C = (1000+273) K = 1273 K
Final temperature, T2 = 25°C = (25+273) K = 298 K
Final pressure, P2 = 30.43 atm
To Find:
Initial pressure inside the scuba tank before it was cooled, i.e., P1.
Calculation:
- Applying Gay - Lussac's Law to the given condition of scuba tank :
P1 / T1 = P2 / T2
⇒ P1 = P2 ×T1 / T2
⇒ P1 = (30.43 × 1273) / 298
⇒ P1 = 129.99 atm ≈ 130 atm
- The initial pressure inside the scuba tank before it was cooled is approximately 130 atm.
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