Chemistry, asked by loganvacanti, 8 months ago

Calculate the initial pressure inside a scuba tank before it cooled from 1000 °C to 25.0 °C. The final pressure in the tank is 30.43 atm

Answers

Answered by Jasleen0599
0

Given:

Initial temperature, T1 = 1000 °C = (1000+273) K = 1273 K

Final temperature, T2 = 25°C = (25+273) K = 298 K

Final pressure, P2 =  30.43 atm

To Find:

Initial pressure inside the scuba tank before it was cooled, i.e., P1.

Calculation:

- Applying Gay - Lussac's Law to the given condition of scuba tank :

P1 / T1 = P2 / T2

⇒ P1 = P2 ×T1 / T2

⇒ P1 = (30.43 × 1273) / 298

P1 = 129.99 atm ≈ 130 atm

- The initial pressure inside the scuba tank before it was cooled is approximately 130 atm.

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