Question

Calculate the instantaneous power of a body rotating with angular velocity of 20rad//s^(-2), when an external torque of 5 Nm is applied to it. Hint : P=tau omega.

Answer 1

Answer:

• The Instantaneous Power of the body will be 100 Watts.

Given:

1. Angular velocity (ω) = 20 rad / sec.
2. Torque acting (τ) = 5 N-m

Explanation:

$\rule{300}{1.5}$

From the formula we know,

⇒ P = τ ω

Where,

• P Denotes Power.
• τ Denotes Torque.
• ω Denotes Angular velocity.

Now,

⇒ P = τ ω

Substituting the values,

⇒ P = 5 N-m × 20 rad / sec

⇒ P = 5 × 20

⇒ P = 100

⇒ P = 100 watts.

∴ The Instantaneous Power of the body will be 100 Watts.

Note:

Angular Power is Analogue of Mechanical Power.

$\rule{300}{1.5}$

$\rule{300}{1.5}$

Extra Formulas:

• τ = r × F
• L = r × P
• I = Σ M r²

• L = I ω
• τ = d L / d t
• τ = I α

Note:

Symbols have there usual meaning.

$\rule{300}{1.5}$

Answer 2

$\huge\underline\mathtt\red{Answer:-}$

•The Instantaneous Power of the body will be 100 Watts.