Question

calculate the intensity of electric field point 50 cm from charge of 4 * 8 * 10 ^ - 6 a Cowomb in a medium of dielectric Constant 3.2 at​

Answer 1

Answer:

The intensity of the electric field at a point 50 cm from a charge of $32*10^{-6}C$   in a medium of dielectric constant 3.2 is  $36*10^{4} N/C$

Explanation:

The electric field is described as the electric force per unit charge

The electric field due to a charge $q$ at a distance $r$ in a medium given by the formula

$E=\frac{1}{4\pi \varepsilon _0k}\frac{q}{r^2}$

where $k$ is the dielectric constant of the medium and

from the question, we have

the charge is $q=32*10^{-6}C$

and the distance at which the electric field is to be calculated  $r=50cm=0.50m$

the dielectric constant of the medium $k=3.2$

now substitute the given values to get the electric field is

$E=\frac{9*10^{9}*32*10^{-6} }{3.2*0.50^{2} } =36*10^{4}N/C$