Question

calculate the internal energy change for the process in which 1 kj of heat is added to 1.2dm3 of oxygen gas in a cylinder at constant pressure of 1 atm and the volume changes to 1.5dm3​

Answer 1

Answer:u=969.61j

Explanation:

h=u+w

u=h-w

w=p[v2-v1]

1atmdm3=101.3j