calculate the ionic strength (M) of 50 ml 0.75% (w/v) NaCl solution
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Answer:
0.75M= P mol = 0.050L.
0.050L=P = mol.
0.0375 = P = mol.
0.0375 mol NaCl P 58.44g.
Nacl
1mol = NaCl
=2.19 grams
NaCl
Explanation:
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