Calculate the ionic strength (m) of 50 ml of 0.75 % (w/v) nacl solution
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0
MOLARITY = MOL
_____
L
M = 0.75 M
V = 50 mL or 0.050 L
moles = P
moles = P
0.75M= P mol = 0.050L
0.050L=P = mol
0.0375 = P = mol
===============
0.0375 mol NaCl P 58.44g
NaCl
1mol = NaCl
=2.19 grams NaCl
_____
L
M = 0.75 M
V = 50 mL or 0.050 L
moles = P
moles = P
0.75M= P mol = 0.050L
0.050L=P = mol
0.0375 = P = mol
===============
0.0375 mol NaCl P 58.44g
NaCl
1mol = NaCl
=2.19 grams NaCl
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Answer:0.125
Explanation:
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