Question

Calculate the ionization energy of hydrogen atom using Bohr's theory. marks 5

Answer 1

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Answer 2

Answer:The ionization energy of hydrogen atom using Bohr's theory is $2.18\times 10^{-26} J$

Explanation:

$n_i=1,n_f=\infty$

$E=h\nu=\frac{hc}{\lambda }$

$\frac{1}{\lambda }=R(\frac{1}{n_{i}^{2}}-\frac{1}{n_{f}^{2}})$

$\frac{1}{\lambda }=1.097\times 10^7 m^{-1}(\frac{1}{1^{2}}-\frac{1}{\infty}^{2}})$

$\frac{1}{\lambda }=1.097\times 10^7 m^{-1}$

$E=6.626\times 10^{-34}J s\times 3\times 10^8 m/s\times 1.097\times 10^7 m^{-1}=2.18\times 10^{-26} J$

The ionization energy of hydrogen atom using Bohr's theory is $2.18\times 10^{-26} J$