calculate the ionization energy of Li2+
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The formula for Ionisation Energy (I.E.) is :
I.E.= 13.6*Z^2/n^2
Here, Z=atomic no.
And n=the no. of shell
➡️By applying the formula we get:
I.E(Energy)=13.6×(3)^2/1
=13.6 ×9 =122.4 eV✔️
Hope this helps!!
I.E.= 13.6*Z^2/n^2
Here, Z=atomic no.
And n=the no. of shell
➡️By applying the formula we get:
I.E(Energy)=13.6×(3)^2/1
=13.6 ×9 =122.4 eV✔️
Hope this helps!!
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