Question

Calculate the KE of ejected electron when the difference in

threshold frequency and frequency of radiations is 5 × 10^14 s-1
. (h = 6.63 × 10^-34 Js).



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Answer 1

Answer:

We have E = h ν ∴ E = (6.63 x 10-34) x (5.0 x 10 14)= 3.315 x 10-29 J. Ans: The energy of the photon is 3.315 x 10-29 J. Example – 06: The photoelectric work function of silver is 3.315 eV. Calculate the threshold frequency and threshold wavelength of silver. Given: Work function of silver = Φ = 3.315 eV = 3.315 x 1.6 x 10-19 J, speed of light = 3 x 10 8 m/s, Planck’s constant = h = 6.63 x 10-34 Js

Explanation:

Answer 2

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