Question

Calculate the kineti energy of the ejected electron if
the radiation of wavelength 8.2 x 10^-8 m fall on it
[h=6.6*10^-34 Js ]​

Answer 1

Answer:

Explanation:

K.E = hν

h= plank's constant

ν= frequency of radiation

this formula can be modified as K.E = h (c/λ)

by substituting

K.E = 6.6* 10⁻³⁴ * 3* 10⁸ / 8.2 * 10⁻⁸

       = 2.414 * 10 ⁻³⁴⁺¹⁶

       = 2.414 * 10⁻¹⁸ J

since K.E of electron is considered we may use electron volt to express it

K.E = 2.414 * 10⁻¹⁸ / 1.6 * 10⁻¹⁹

      = 1.508 *10

       = 15.08 eV

hope it helps

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