Question

calculate the kinetic energy and potential energy of mean position and extreme position of mass spring system​

Answer 1

Answer:

calculate the kinetic energy and potential energy of mean position and extreme position of mass spring system

7

Answer 2

Answer:

U0=21KA2=Umax

4+21kA2=20

or 21kA2=16 J

(1) U=U0+21kX2

       =U0+21k(2A)2

       =4+416=8 J

(2) KE=21k(A2−16A2)

       =1615(21kA2)=1615×16=15 J

(3) KE=

21k(A2−0)

       =21kA2=16 J

(4) KE=21k(A2−4A2)

       =43(21kA2)=43(16J)=12 J