Question

Calculate the kinetic energy in the given cases

(i) Mass = 100 kg, Velocity = 50 m/s

(ii) Mass = 600 kg, Velocity = 200 m/s

(iii) Mass = 1000 kg, Initial Velocity = 200 m/s, final Velocity = 500 m/s​

Answer 1

Answer (i) :-

Given :-

• Mass (m) → 10 kg
• Velocity (v) → 50 m/s

To Find :-

• Kinetic Energy

Formula Used :-

• $\underline{ \boxed{\pink{ \sf\dfrac{1}{2} m {v}^{2} }}}$

Subsisting Values

$\sf\implies \cancel{\dfrac{1}{2} \times 10} \times ( {50)}^{2}$

$\sf\implies5 \times 2500$

$\sf\implies 12500$

Thus, 12500 Joule

Answer (ii) :-

Given :-

• Mass (m) → 600 kg
• Velocity (v) → 200 m/s

To Find :-

• Kinetic Energy

Formula Used :-

• $\underline{ \boxed{\pink{ \sf\dfrac{1}{2} m {v}^{2} }}}$

Subsisting Values

$\sf\implies \cancel{\dfrac{1}{2} \times 600} \times ( {200)}^{2}$

$\sf\implies 300 \times 40000$

$\sf\implies 1200000$

Thus, 1200000 Joule

Answer (iii) :-

Given :-

• Mass (m) → 1000 kg
• Initial Velocity (u) → 200 m/s
• Final Velocity (v) → 500 m/s

To Find :-

• Kinetic Energy

Formula Used :-

• $\underline{ \boxed{\pink{ \sf\dfrac{1}{2} m({v}^{2 } - {u}^{2}) }}}$

Subsisting Values

$\sf\implies \cancel{\dfrac{1}{2} \times 1000} \bigg( ( {500)}^{2} - ( {200)}^{2} \bigg)$

$\sf\implies 500 \times 250000 - 4000$

$\sf\implies 500 \times 210000$

$\sf\implies 105000000$

Thus, 105000000 Joule

Hence, Solved ♡

Answer 2

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