Calculate the kinetic energy of 0.5moles of h2 at 27c (r=2 can mol
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Explanation:
okjKE = (3/2)nRT where n is the no. of molecules of the gas, R is ideal gas constant and T is temperature in Kelvin. 8g CH4 = 8/16 = 0.5 mol KE = (3/2)•0.5•8.314•300
KE = 1870.65 J
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