Calculate the kinetic energy of 2 moles of nitrogen at 27°
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K.E. of 1 mole N2 gas = (3/2)*8.314*300 J
= 3741.3 J
Thus K.E. of 2 moles N2 gas = 2*3741.3 J
= 7482.6 J
HOPE THIS COULD HELP U ... :) :)
= 3741.3 J
Thus K.E. of 2 moles N2 gas = 2*3741.3 J
= 7482.6 J
HOPE THIS COULD HELP U ... :) :)
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