Question

Calculate the kinetic energy of 2moles of Argon at 27°C

Answer 1

Answer:

72

Explanation:

H. O . P. E. I. T. H. E. L. .S

PLEASE MARK IT AS BRAINIEST

Answer 2

Answer:73.89

Explanation: formula of kinetic energy = 3/2 nRT

HERE n = 2     R=0.0821        T = 300 K

3/2 x (2) x (0.0821) x (300)

=73.89