Question

calculate the kinetic energy of 3 moles of co2 at 27 degrees​

Answer 1

Answer:

Kinetic energy =3/2nRT n=3moles R=8.314,T=300k KE=3/2.3.8.314.300=11223.9J

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Answer 2

Answer:

Hey buddy Mark the answer brainliest.

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No.of moles=3

Temperature =27+273=300k

R=2cal

K e=3/2 net

3/2×3×2×300=2700