Question

Calculate the kinetic energy of 4 moles of methane at -73°c

Answer 1

Answer:

Total kinetic energy = n (3/2 RT0

where n = Number of moles of the gas

R = Gas constant

T = Absolute temperature

Molecular weight of methane,

CH4 = 12 + 4 * 1 = 16

∴ Number of moles of methane in 8.0 gm of methane

= 8.0/16.0 = 0.5

R = 8.314 joules/K/mole

T = 27 + 273 = 300 K

∴ Total kinetic energy of the molecules in 8.0 gm of methane at 27oC = InI * 3/2 RT

= 0.5 * 3/2 * 8.314 * 300 = 1870.65 joules

∴ Average kinetic energy = 1870.65/6.023 *1023 *0.5

= 6.21 * 10-21 joules/molecular e....mRk me as brain list

Answer 2

Answer:

n = No of moles of methane
=4g/16gmol=0.25mol

R = 8.314J mol–1K–1;
T= –73°C + 273 = 200 K
Kinetic energy
=32×0.25mol×8.314Jmol−1K−1×200K

= 623.6J