Question

Calculate the kinetic energy of 5 moles of nitrogen at 27 degree celsius

Answer 1

Kinetic energy of the ideal gas can be calculated as

Kinetic energy = {3*n*R*T} / 2

where,

n = number of moles

R = gas constant

T = temperature in kelvin

We have above is, n = 5 moles of N

R = 8/314,

and T = 27 + 273 (to convert celsius to kelvin, add 273)=300.

Kinetic energy = {3*5*8.314*300} / 2

= 18,706.05 joules or 18.706 kj

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Answer 2

HLO MATE HERE U GO

⭐. Given that :

No . of moles of n = 5 moles

T = ( 27 + 273) k = 300 k

R = 8.3 14 J mol ^1 k ^1

K. E = 3/2 nRT

==> 3/2 × 5 × 8.314 × 300

==> 18706. 50J//