Question

Calculate the kinetic energy of 5mole of nitrogen gassed at 27•c

Answer 1

Answer:

Kinetic energy of the ideal gas can be calculated as

Kinetic energy = ( 3*n*r*t)/2

let's

n = number of moles

t = temperature in Kelvin

r = gas constant

We have above is ,n = 5 moles of n

r = 8/314

and T = 27+273 ( to convert celsius to Kelvin ,add 273 ) = 300

Kinetic energy= (3*5*8.314*300)/2

= 18,706.05 joules or 18.706kj