Question

Calculate the kinetic energy of a 71 kg man walking at 1 m/s.

Answer 1

Answer:

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Explanation:

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Answer 2

$K.E= \frac{1}{2} m {v}^{2}$

$K.E = \frac{1}{2} \times 71 \times {1}^{2}$

$K.E = 35.5J$