Calculate the kinetic energy of a body of mass 0.1 kg & momentum 40kg ms/s.
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Answered by
1
momentum p = mv
K.E. = 1/2mv^2
=(mv)^2/2m
(p)^2/2m
K.E. =40×40/0.1
=16000J = 16 KJ
K.E. = 1/2mv^2
=(mv)^2/2m
(p)^2/2m
K.E. =40×40/0.1
=16000J = 16 KJ
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gohan1:
yeah sorry i forgot to divide it by 2
That s the matter
Hope you understand
yeah sorry i forgot to divide it by 2
answer would be 8 kj right
K.E=1/2 mv2 ; p×v/2
tx
p×v/2 =(p)^2/2m
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nvrmnd
Answered by
3
kinetic energy = 8000joules
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i agree image now very well seen and the answer is 8000joules
abt wic image this is my first image
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tx
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