Question

calculate the kinetic energy of a body of mass 2 kilogram moving with a velocity of 0.1 M per second

Answer 1

$<h1 > heya$

$<h5 > answer$

K.e =
$\frac{1}{2} mv {}^{2}$

$\frac{1}{2} \times 2 \times 0.1*0.1$

0.01 j

Hope it helps you

@ Prabhudutt

$<tt > mark as brainliest$

Answer 2

Formula :

Kinetic energy = 1/2 × m v²

Given :

Mass = 2 kg

Velocity = 0.1 m/s

Kinetic energy = 1/2 m v²

                        = 1/2 × 2 kg × ( 0.1 m/s )²

                        = 1 kg × 0.01 m²/s²

                        = 0.01 J

ANSWER :

The kinetic energy is 0.01 J