Question

Calculate the kinetic energy of a body of mass 50 kg moving with 5 ms​

Answer 1

Given:

$\qquad \begin{cases} &\sf \sf{\pink{Mass = 5kg}} \\&\sf{\green{Velocity = 5m/s}} \end{cases}$

Find:

$\\ \qquad \begin{cases} &\sf \sf{\red{Kinetic \: Energy \: of \: the \: body}}\end{cases}$

Solution:

we, know that

↬ $\textsf{Kinetic Energy} \sf = \dfrac{1}{2}mv^2$

where,

• m = 50kg
• v = 5m/s

• Substituting these values •

↦$\textsf{Kinetic Energy} \sf = \dfrac{1}{2}mv^2$

↦$\textsf{Kinetic Energy} \sf = \dfrac{1}{2}\times 50 \times (5)^2$

↦$\textsf{Kinetic Energy} \sf = \dfrac{1}{2}\times 50 \times 25$

↦$\textsf{Kinetic Energy} \sf = \dfrac{1}{2}\times 1250$

↦$\textsf{Kinetic Energy} \sf = \dfrac{1250}{2}$

↦$\textsf{Kinetic Energy} \sf = 625J$

Hence, Kinetic Energy of the body will be 625J

Answer 2

$\sf Given \: that \begin{cases} & \sf{Mass \: of \: body = \: \bf{50 \: kg}} \\ & \sf{Velocity = \: \bf{5 \: m/s}} \end{cases}$

$\sf To \; find \begin{cases} & \sf{Kinetic \: energy} \end{cases}$

$\sf Solution \begin{cases} & \sf{Kinetic \: energy = \: \bf{625 \: J}} \end{cases}$

${\large{\rm{\underline{Using \; formula}}}}$

$\: \: \: \:{\boxed{\boxed{\sf{\longrightarrow Kinetic \: energy = \: \dfrac{1}{2}mv^{2}}}}}$

~ Let's find Kinetic Energy

$\: \:{\sf{\longmapsto Kinetic \: energy = \: \dfrac{1}{2}mv^{2}}}$

Where,

${\bullet{\leadsto}}$ m denotes mass.

${\bullet{\leadsto}}$ v denotes velocity.

Here,

${\bullet{\leadsto}}$ m is 50 kg

${\bullet{\leadsto}}$ v is 5 m/s

$\: \: \: \: \:{\sf{\longmapsto Kinetic \: energy = \: \dfrac{1}{2} \times 50 \times (5)^{2}}}$

$\: \: \: \:{\sf{\longmapsto Kinetic \: energy = \: \dfrac{1}{2} \times 50 \times 25}}$

$\: \:{\sf{\longmapsto Kinetic \: energy = \: \dfrac{1}{2} \times 1250}}$

$\: \: \: \: \: \:{\sf{\longmapsto Kinetic \: energy = 625 \: Joules}}$

${\pink{\frak{Henceforth, \: kinetic \: energy \: is \: 625 \: J}}}$

${\large{\rm{\underline{\underbrace{Additional \; knowledge}}}}}$

$\red \bigstar \boxed{ \sf{Pressure = \frac{normal \: force}{area}}}$

$\begin{gathered} \\ \red \bigstar \boxed{ \sf{Force = mass \times acceleration}} \end{gathered}$

$\red \bigstar {\boxed{ \sf{Power = \dfrac{energy}{time}}}}$

$\red \bigstar \boxed{ \sf{Intensity = \dfrac{energy}{area \times time}}}$

$\begin{gathered}\\ \red\bigstar\boxed{\sf{\omega=\dfrac{2 \pi}{t}}}\end{gathered}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Maxwell \: is \: unit \: of \: magnetic \: flux}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: magnetic \: flux \: is \: Weber}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: surface \: tension \: is \: \dfrac{N}{m}}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: mechanical \: power \: is \: Watt}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Number \: of \: SI \: units \: are \: 7}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Ampere \: is \: the \: unit \: of \: current \: electricity}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: Young's \: modulus \: of \: elasticity \: is \: Newton/m^{2}}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: pressure \: is \: Pascal}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Curie \: is \: the \: unit \: of \: radio \: activity}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto Decibel \: is \: the \: unit \: of \: intensity \: of \: sound}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: electric \: charge \: is \: coulomb}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: resistance \: is \: ohm}}}$

$\; \; \; \; \; \; \;{\sf{\bold{\leadsto SI \: unit \: of \: acceleration \: is \: ms^{-2}}}}$