Chemistry, asked by varshithagutti, 6 months ago

calculate the kinetic energy of an electron by an atom by 400nm light when it's threshold wave length is600nm

Answers

Answered by shivamsharma215
0

Explanation:

Here, λ=600nm,λ

=400nm,K

max

=2K

max

According to Einstein photoelectric equation

K

max

=

λ

hc

−ϕ

0

and 2K

max

=

λ

hc

−ϕ

0

Dividing by we get

2=

λ

hc

−ϕ

0

λ

hc

−ϕ

0

or

λ

2hc

−2ϕ

0

=

λ

hc

−ϕ

0

λ

2hc

−2ϕ

0

=

λ

hc

−ϕ

0

Or hc(

λ

2

λ

1

)=ϕ

0

∴ϕ

0

=1240eVnm(

600nm

2

400nm

1

)=1.03eV

Similar questions