calculate the kinetic energy of an electron by an atom by 400nm light when it's threshold wave length is600nm
Answers
Answered by
0
Explanation:
Here, λ=600nm,λ
′
=400nm,K
max
′
=2K
max
According to Einstein photoelectric equation
K
max
=
λ
hc
−ϕ
0
and 2K
max
=
λ
′
hc
−ϕ
0
Dividing by we get
2=
λ
hc
−ϕ
0
λ
′
hc
−ϕ
0
or
λ
2hc
−2ϕ
0
=
λ
′
hc
−ϕ
0
λ
2hc
−2ϕ
0
=
λ
′
hc
−ϕ
0
Or hc(
λ
2
−
λ
′
1
)=ϕ
0
∴ϕ
0
=1240eVnm(
600nm
2
−
400nm
1
)=1.03eV
Similar questions
English,
3 months ago
Math,
3 months ago
Computer Science,
3 months ago
Social Sciences,
6 months ago
Math,
6 months ago
Math,
10 months ago
Geography,
10 months ago
History,
10 months ago