Question

calculate the kinetic energy of an object of mass 30 Kg whose velocity increases which attain 60 Km per hour staring from rest?

Answer 1

so v = 60 km/h = 50/3 m/s

so m = 30 kg

so KE = $\frac{1}{2}mv^2$ = 250 J

Answer 2

m = 30 kg
velocity = 60 km/h = 60*5/18 m/s = 50/3 m/s
KE = 0.5*m*v^2 = 0.5*30*(50/3)^2 = 4166.67 J