Question

Calculate the kinetic energy of the electron emitted by an atom by 400nm light when it's threshold wavelength is 600nm . Friends pls answer correctly pls

Answer 1

Explanation:

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Answer 2

A

1.03 eV

ANSWER

 Here, λ=600nm,λ′=400nm,Kmax′=2Kmax

According to Einstein photoelectric equation

Kmax=λhc−ϕ0

and 2Kmax=λ′hc−ϕ0

Dividing by we get 

2=λhc−ϕ0λ′hc−ϕ0      or   λ2hc−2ϕ0=λ′hc−ϕ0

λ2hc