Question

Calculate the lattice energy of formation of NaCl from the following data: Na(s) + ½CL2(g) → NaCl(s) ∆HF=-411.3KJ.mol-¹
Heat of sublimation of Na(s) = 108.7KJ.mol-¹ Ionisation of energy of Na(g) = 495.0 KJ.mol-¹
Dissociation energy of Cl2(g) = 244 KJ.mol-¹
Electron affinity of Cl(g) = -349.0 KJ.mol-1 ​

Answer 1

Answer:

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