Question

Calculate the Lattice enthalpy of CaCl, given that the enthalpy of
(i) Sublimation of Ca = 121 KJ/mol
(ii) Dissociation of Cl2 to Cl = 242.8 KJ/mol.
(iii) Ionisation of Ca to Ca2+ = 2422 KJ/mol.
(iv) Electron gain enthalpy for CI to Cl- = -355 KJ/mol.
(v) enthalpy of formation of CaCl2(s) = -795 KJ/mol.
1) +2780.8 KJ/mole 2) -2870.8 KJ/mole 3) 2075.8 KJ/mole
4) -2075.8 KJ/mole​

Answer 1

Answer:

Dissociation of Cl2 to Cl = 242.8 KJ/mol.

(iii) Ionisation of Ca to Ca2+ = 2422 KJ/mol.

(iv) Electron gain enthalpy for CI to Cl- = -355 KJ/mol.

(v) enthalpy of formation of CaCl2(s) = -795 KJ/mol.

1) +2780.8 KJ/mole 2) -2870.8 KJ/mole 3) 2075.8 KJ/mole