Question

calculate the length and orientation of a rod 2m in a frame of reference which is moving with velocity with 0.6c in a direction making an angle 30 degree with the rod

Answer 1

explanation is up

hope this is helpful

Answer 2

Length as it appears to an observer on the earth is 0.8m

0.8

m

Given:

Calculate the length and orientation of a rod 2m in a frame of reference which is moving with velocity with 0.6c

To Find:

Length as it appears to an observer on the earth

Solution:

An object moving at a speed v relative to an observer will appear to contract from both frames of reference, though with the object's frame of reference it is the observer being contracted. This happens all the time but the speeds are always too slow to have any noticeable effect, only being noticeable at relativistic speeds.

Formula for length contraction is L,

= $L_{0} \sqrt{1 - \frac{v^2}{c^2} }$

where,

L = new length (m)

L0= original length (m)

v = speed of object (ms−1)

c = speed of light (~3.00⋅10^8ms−1)

So,

= $L_{0} \sqrt{1 - \frac{v^2}{c^2} }$

= $\sqrt{1 - 0.6^2}$

= $\sqrt{1 - 0.36}$

= $\sqrt{0.64}$

=0.8m

Hence, we get the value of the length as it appears to an observer on the earth is 0.8m

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